Age of mother 10 years ago was 3 times the age of her son. After 10 years, mother’s age will be twice that of his son. Find the ratio of their present ages.

Question: Age of mother 10 years ago was 3 times the age of her son. After 10 years, mother’s age will be twice that of his son. Find the ratio of their present ages.Solution:We are given that, age of mother 10 years ago was 3 times the age of her sonSo, let age of son be x and as mother’s age is 3 times the age of her son, let it be 3x, three years ago.At present: Mother’s age will be (3x + 10) and son’s age will be (x + 10)After 10 years: Mother’s age will be (3x + 10) +10 and son’s age will be (x + 10) + 10Mother’s age is twice that of son(3x + 10) +10 = 2 [(x + 10) + 10](3x + 20) = 2[x + 20]Solving the equation, we get x = 20We are asked to find the present ratio.(3x + 10) : (x + 10) = 70 : 30 = 7 : 3