[{(a² + b²)/2ab} - 1] ÷ [{(a³ - b³)/(a - b)} - 3ab] = কত?

প্রশ্ন: [{(a² + b²)/2ab} - 1] ÷ [{(a³ - b³)/(a - b)} - 3ab] = কত?

সমাধান:
[{(a² + b²- 2ab)/2ab} ÷ [{a³ - b³- 3ab(a - b)}/(a - b)]
[(a - b)²/2ab]÷ [{(a - b)³}/(a - b)]
[(a - b)²/2ab] ×[(a - b)/(a - b)³]
= 1/2ab