(a² + b² - c² + 2ab)/(a² - b² + c² + 2ac) = কত?

প্রশ্ন: (a² + b² - c² + 2ab)/(a² - b² + c² + 2ac) = কত?

সমাধান:
(a² + b² + c² + 2ab)/(a² - b² + c² + 2ac)
= {(a + b)² - c²}/{(a + c)² - b²}
= (a + b + c)(a + b - c)/(a + b + c) (a - b + c)
= (a + b - c)/(a - b + c)