A worker was hired for 7 days. Each day, he was paid Tk. 10 more than what he was paid for the previous day of work. The total amount he has paid in the first 4 days of work equaled the total amount he was paid in the last 3 days. What was his starting pay?

Question: A worker was hired for 7 days. Each day, he was paid Tk. 10 more than what he was paid for the previous day of work. The total amount he has paid in the first 4 days of work equaled the total amount he was paid in the last 3 days. What was his starting pay?

Solution:
ধরি,
প্রথম দিনের বেতন = x টাকা
প্রতিদিন বেতন 10 টাকা করে বৃদ্ধি পাচ্ছে,
1ম দিন = x
2য় দিন = x + 10
3য় দিন = x + 20
4র্থ দিন = x + 30
5ম দিন = x + 40
6ষ্ঠ দিন = x + 50
7ম দিন = x + 60

ATQ,
প্রথম ৪ দিনের মোট = শেষ ৩ দিনের মোট

প্রথম ৪ দিনের বেতনের যোগফল,
= x + (x+10) + (x+20) + (x+30)
= 4x + 60

শেষ ৩ দিনের বেতনের যোগফল,
= (x+40) + (x+50) + (x+60)
= 3x + 150

ATQ,
4x + 60 = 3x + 150
⇒ x = 150 - 60
⇒ x = 90