A train 108 m long moving at a speed of 50 km/hr crosses a train 112m long coming from opposite direction in 6 seconds. The speed of the second train is-

Question: A train 108 m long moving at a speed of 50 km/hr crosses a train 112m long coming from opposite direction in 6 seconds. The speed of the second train is-

Solution:
Distance covered = (108 + 112)
= 220 meter.
and Time = 6 seconds.

∴ Relative speed = (220/6) = (110/3) m/s.
= (110 × 3600)/(3 × 1000) km/hr
= 132 km/hr

Now,
50 + Speed of second train = 132 km/hr

∴ Speed of second train = (132 - 50) km/hr
= 82 km/hr.