A thief steals a car at 1.30 pm and drive it off 40 km/hr. The theft is discovered at 2 pm and the owner sets off in another car at 50 km/hr he will catch the thief at-

Question: A thief steals a car at 1.30 pm and drive it off 40 km/hr. The theft is discovered at 2 pm and the owner sets off in another car at 50 km/hr he will catch the thief at-

Solution:
Distance covered by thief in (2 pm - 1.30 pm) = 1/2 hours

1/2 hours at speed of 40 km/h = 40 × (1/2) = 20 km

Their relative speed in same direction = (50 - 40) km/h
= 10 km/h

ATQ,
20 km, is the distance that has to be covered by owner to catch the thief.

Required time = (20/10) hours
=2 hours

Therefore, he will over take the thief at :
= 2 pm + 2 hours
= 4 pm