A takes twice as much as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 3 days. A can do the work alone in -

Question: A takes twice as much as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 3 days. A can do the work alone in -

Solution:
Let, A, B, and C take 6x, 6x/2 = 3x, and 6x/3 = 2x respectively

Now,
(1/6x) + (1/3x) + (1/2x) = 1/3
⇒ 6/6x = 1/3
⇒ 1/x = 1/3
⇒ x = 3

So, A takes = 6 × 3 = 18 days