A sum of Tk. 1800 has been divided among A, B and C such that A gets 1/2 of what B gets and B gets 1/3 of what C gets. C's share is-

Question: A sum of Tk. 1800 has been divided among A, B and C such that A gets 1/2 of what B gets and B gets 1/3 of what C gets. C's share is-

Solution:
Let, C's share = Tk. x
Then, B's share = Tk. x/3,
A's share = Tk. (1/2)(x/3) = Tk. x/6

∴ x/6 + x/3 + x = 1800
⇒ (x + 2x + 6x)/6 = 1800
⇒ 9x/6 = 1800
⇒ x = (1800 × 6)/9
⇒ x = Tk. 1200

∴ C's share = Tk. 1200