A student obtained 60, 75 and 85 marks respectively in 3 monthly examinations in physics and 95 marks in the final examination. The 3 monthly examinations are the equal weightage whereas the final examination is weighted twice as much as monthly examination. What is his average mark in physics?

Question: A student obtained 60, 75 and 85 marks respectively in 3 monthly examinations in physics and 95 marks in the final examination. The 3 monthly examinations are the equal weightage whereas the final examination is weighted twice as much as monthly examination. What is his average mark in physics?

Solution:
Let the weightage of each monthly examination be 1 unit.
So, the weightage of the final examination = 2 units.

Total weighted marks obtained = (60 × 1) + (75 × 1) + (85 × 1) + (95 × 2)
= 60 + 75 + 85 + 190
= 410

Total weightage = 1 + 1 + 1 + 2 = 5 units.

Average mark = Total weighted marks/Total weightage
= 410/5
= 82

Correct Option: ক) 82