A runs twice as fast as B and B runs thrice as fast as C. The distance covered by C in 144 minutes, will be covered by A in:

Question: A runs twice as fast as B and B runs thrice as fast as C. The distance covered by C in 144 minutes, will be covered by A in:

Solution:
Let,
The speed of C = x
So the speed of B = 3x
and the speed of A = 3x × 2
= 6x

Ratio of speed A : B : C = 6x : 3x : x
= 6 : 3 : 1

Then ratio of time taken = 1/6 : 1/3 : 1
= 1 : 2 : 6

Hence, time taken by A = 144/6 minutes
= 24 minutes