A monkey climbs a 36 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top?

Question: A monkey climbs a 36 m high pole. In first minute he climbs 6 m and slips down 3 m in the next minute. How much time is required by it to reach the top?

Solution:
According to the question,
For 1^st min, he climbs 6 m and comes down 3 m in 2^nd
Effectively in 2 min, he climbs 3 m.

In 1 min, he climbs (3/2) m

So, in 20 mins he climbs = (3/2) × 20 = 30 m

So, in the 21^th minute, he climbs the next 6 m.

∴ The required value is 21 minutes.