A merchant has three different types of oil: 240 litres, 300 litres, and 420 litres. Find the minimum number of containers of equal size that can store the oil without mixing.

Question: A merchant has three different types of oil: 240 litres, 300 litres, and 420 litres. Find the minimum number of containers of equal size that can store the oil without mixing.

Solution:
The size of each container should be the greatest possible that divides all three quantities, i.e., H.C.F of 240, 300, and 420.

H.C.F(240, 300, 420) = 60 litres

Total oil = 240 + 300 + 420 = 960 litres

Number of containers required = 960/60 = 16