A is twice as good as workman as B and therefore is able to finish a job in 45 days less than B. Working together, they can do it in-

Question: A is twice as good as workman as B and therefore is able to finish a job in 45 days less than B. Working together, they can do it in-Solution:Let, B can do the work in x days.A can do the work in (x - 45) days. ATQ, A is twice efficient as compared to B.(x - 45) = x/2 ⇒ 2(x - 45) = x ⇒ 2x - 90 = x ⇒ 2x - x = 90∴ x = 90 daysB can do the work in 90 days while A can do the work in 45 days. A's 1 day's work = 1/45 part B's 1 day's work = 1/90 part (A + B)'s 1 day's work = (1/45 + 1/90) part = (2 + 1)/90 part= 3/90 part= 1/30 partTotal time taken by A and B together to complete the work = 30 days