A is faster than B. A and B each walk 24km. The sum of their speeds is 7km/hr and the sum of times taken by them is 14 hours. Then, A's speed is equal to -

Question: A is faster than B. A and B each walk 24km. The sum of their speeds is 7km/hr and the sum of times taken by them is 14 hours. Then, A's speed is equal to -

Solution:
Let, A's speed be = x km/hr
B's speed is = (7 - x) km/hr

ATQ,
24/x + 24/(7 - x) = 14
or, {24(7 - x) + 24x}/{x(7 - x) = 14
or, 24(7 - x) + 24x = 14x(7 - x)
or, 14x² - 98x + 168 = 0
or, x² - 7x + 12 = 0
or, (x - 3)(x - 4) = 0
∴ x = 3 or, x = 4

as A's speed is greater than B.
so, x = 4