A can complete a piece of work in 18 days, B in 20 days and C in 30 days, B and C together start the work and forced to leave after 2 days. The time taken by A alone to complete the remaining work is:

Question: A can complete a piece of work in 18 days, B in 20 days and C in 30 days, B and C together start the work and forced to leave after 2 days. The time taken by A alone to complete the remaining work is:Solution:(B+C) 2 day's work:2 × ( 1/20 + 1/30 ) = 2 × (3+2)/60= 1/6 partRemaining work = 1−1/6= 5/6 partA's one day's work= 1/18 part Time taken to complete the work= (5/6) / (1/18) daysHence,Time taken to complete the work= 5/6×18=15 days