A and B can do a job together in 7 days. A is 1.75 times as efficient as B. The same job can be done by A alone in-

Question: A and B can do a job together in 7 days. A is 1.75 times as efficient as B. The same job can be done by A alone in-Solution:1.75 = 175/100 = 7/4(A's 1 day's work) : (B's 1 day's work) = 7/4 : 1 = 7 : 4.Let A's and B's 1 day's work be 7x and 4x respectively.Then, 7x + 4x = 1/7⇒ 11x = 1/7⇒ x = 1/77A's 1 day's work = (1/77) × 7 = 1/11∴ A can do the work in 11 days.