5 men undertook a piece of work and finished half the work in 18 days if two men drop out, in how many days the remaining work will be completed?

Question: 5 men undertook a piece of work and finished half the work in 18 days if two men drop out, in how many days the remaining work will be completed?

Solution:
5 men completed half of the work in 18 days so the entire work will be completed in 36 days.
5 men' one day work will be = 1/36
One man's one day work = 1/(36 × 5) = 1/180

Two men drop out, so the three men have to complete the remaining work.
Three men's one day work will be = (1/180) × 3 = 1/60

1/60 part of the work is completed by three men in one day
1 or full part of the work is completed by three men in 60 day
1/2 part of the work is completed by three men in 60/2 = 30 day